Difference between revisions of "Team:Aix-Marseille/Integrated Practices/Process"

(Weight of cells needed for importation)
(Weight of cells needed for importation)
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''In a situation with 1 g of initial platinum, during 10h of incubation:  
 
''In a situation with 1 g of initial platinum, during 10h of incubation:  
-the uptake is equal to (2.65*10^(-6)*10)= 2.65*10^(-2) µmol/g of cells (dry wt)    
+
 
 +
-the uptake is equal to (2.65*10^(-6)*10)= 2.65*10^(-2) µmol/g of cells (dry wt)
 +
 
 
-the total of DFHOB to import is 4.68 moles so ((4.68/2.65*10^(-2))/1000)= 176.6 kg of dry cells
 
-the total of DFHOB to import is 4.68 moles so ((4.68/2.65*10^(-2))/1000)= 176.6 kg of dry cells
 +
 
- as the dry weight is en tenth of the wet one and thtat a pellet is composed half by water, the mass of the cell pellet to add will be (176.6*10*2)= 3532 kg ''
 
- as the dry weight is en tenth of the wet one and thtat a pellet is composed half by water, the mass of the cell pellet to add will be (176.6*10*2)= 3532 kg ''
  

Revision as of 21:05, 21 September 2016