Difference between revisions of "Team:Imperial College/QuorumQueens"

(Created page with "{{:Team:Imperial_College/Templates/NavBar}} <html> <div id="mainContent"> <div> class="some-padding" </div> <div class="container"> <h2>Quorum Modelling</h2> <p>...")
 
 
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{{:Team:Imperial_College/Templates/NavBar}}
 
{{:Team:Imperial_College/Templates/NavBar}}
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<html>
 
<html>
  
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<script type="text/x-mathjax-config">
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MathJax.Hub.Config({
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  tex2jax: {inlineMath: [['$','$'], ['\\(','\\)']]}
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});
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</script>
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<script type="text/javascript" async src="https://2015.igem.org/common/MathJax-2.5-latest/MathJax.js?config=TeX-AMS_CHTML"></script>
  
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<head>
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<section>
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<title>MathJax TeX Test Page</title>
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<script type="text/x-mathjax-config">
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  MathJax.Hub.Config({tex2jax: {inlineMath: [['$','$'], ['\\(','\\)']]}});
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</script>
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<script type="text/javascript" async
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  src="https://cdn.mathjax.org/mathjax/latest/MathJax.js?config=TeX-AMS_CHTML">
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</script>
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</head>
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<body>
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When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
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$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
  
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<div id="mainContent">
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</section>
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<div> class="some-padding" </div>
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</body>
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<div class="container">
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    <h2>Quorum Modelling</h2>
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<p>
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</p>
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</div>
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</div>
 
  
  
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<!-- Footer -->
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<!-- Footer Dark-->
 
<aside class="bg-dark">
 
<aside class="bg-dark">
 
   <div class="container text-center">
 
   <div class="container text-center">
 
     <div class="call-to-action">
 
     <div class="call-to-action">
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       <h2>
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       <h2><span class="cream">
 
         Connect With Imperial iGEM
 
         Connect With Imperial iGEM
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       </h2>
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       </span></h2>
 
       <div style="padding: 10px 10px 10px 10px">
 
       <div style="padding: 10px 10px 10px 10px">
 
       <div class="col-xs-4 col-md-4">
 
       <div class="col-xs-4 col-md-4">
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   </div>
 
   </div>
 
</aside>
 
</aside>
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</body>
 
</body>

Latest revision as of 13:34, 11 October 2016


MathJax TeX Test Page When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$