Difference between revisions of "Team:Aix-Marseille/Collaborations"

(Proposition: Adding contention)
(Proposition: Adding contention)
Line 184: Line 184:
 
Nevertheless, this simple model gives:<br/><br/>
 
Nevertheless, this simple model gives:<br/><br/>
  
<div lang="latex">\mu &= \mu_{0} \times e^{-\frac{[Toxin]}{IC_{50}}} \\</div>(12)<br/><br/>
+
<div lang="latex">\mu = \mu_{0} \times e^{-\frac{[Toxin]}{IC_{50}}} \\</div>(12)<br/><br/>
<div lang="latex">[Toxin] &= max(0,\frac{k_1z_1-k_2z_2}{k_3}) \\</div>(13)<br/><br/>
+
<div lang="latex">[Toxin] = max(0,\frac{k_1z_1-k_2z_2}{k_3}) \\</div>(13)<br/><br/>
<div lang="latex">\mu &= \mu_{0} \times min(1.0,e^{-k_a(z_1-k_bz_2)}) \\</div>(14)<br/><br/>
+
<div lang="latex">\mu = \mu_{0} \times min(1.0,e^{-k_a(z_1-k_bz_2)}) \\</div>(14)<br/><br/>
<div lang="latex">k_a &= \frac{k_1}{k_3 \times IC_{50}} \\</div>(15)<br/><br/>
+
<div lang="latex">k_a = \frac{k_1}{k_3 \times IC_{50}} \\</div>(15)<br/><br/>
<div lang="latex">k_b &= \frac{k_2}{k_1}</div>(16)<br/><br/>
+
<div lang="latex">k_b = \frac{k_2}{k_1}</div>(16)<br/><br/>
  
 
Incorporating 2 toxin anti toxin pairs,  
 
Incorporating 2 toxin anti toxin pairs,  

Revision as of 16:41, 17 October 2016