Difference between revisions of "Team:Exeter/Team/collab"

Line 601: Line 601:
 
<p id = "pp">We suspended our sample in a falcon tube in the middle of a  beaker of water. We had one thermocouple that ran through the falcon tube which was attached to a 0.65m of thin plastic coated copper wire (0.05m^2 in diameter).  This wire was hooked up to a current source which provided around 5 Amps and was our heat source used to provide a temperature gradient. A second thermocouple was fitted in the centre of the falcon tube to measure the temperature of the sample. </p>
 
<p id = "pp">We suspended our sample in a falcon tube in the middle of a  beaker of water. We had one thermocouple that ran through the falcon tube which was attached to a 0.65m of thin plastic coated copper wire (0.05m^2 in diameter).  This wire was hooked up to a current source which provided around 5 Amps and was our heat source used to provide a temperature gradient. A second thermocouple was fitted in the centre of the falcon tube to measure the temperature of the sample. </p>
 
  <img src="https://static.igem.org/mediawiki/2016/8/88/T--Exeter--Home_collab_cond.jpg" style="float:right; width:40vw; height:60vh;">
 
  <img src="https://static.igem.org/mediawiki/2016/8/88/T--Exeter--Home_collab_cond.jpg" style="float:right; width:40vw; height:60vh;">
  <p id = "pp">The idea was to measure the differnce in temperature between the wire and the sample over time. We recorded  
+
  <p id = "pp">The aim of the experiment was to measure the difference in temperature between the wire and the sample over time. We recorded the temperature difference over a 10 minute period, producing the graph on the right. The first 50 seconds of data were extracted and the process repeated. We did this at 5 times per sample to obtain a more reliable result.</p>
 
+
the temperature difference for 10 minutes a test and this produced the graph on the right.
+
Once this difference was recorded The first 50 seconds of data were extracted and the process repeated.
+
We did this at least 5 times per sample to obtain a more reliable result. </p>
+
 
   
 
   
  <p id = "pp"> From the data we found the difference in temperature  
+
  <p id = "pp"> Using the data about the difference in temperature, we plotted a straight best fit line using the least squares method. This line was then used to calculate the average gradient of the graph.
With the data we plotted a straight best fit line using the least squares method. This line was then used to calculate the  
+
Following the guidelines in  
average gradient of the graph. Following the guidelines in  
+
 
<a href="http://iopscience.iop.org/article/10.1088/0022-3735/14/12/020/pdf">this paper</a> we knew that We could use
 
<a href="http://iopscience.iop.org/article/10.1088/0022-3735/14/12/020/pdf">this paper</a> we knew that We could use
 
$$ \lambda = \frac{Q}{4\pi[T(t_{2})-T(t_{1})]}\  \log{\Big(\frac{t_{2}}{t_{1}}\Big)}$$</p>
 
$$ \lambda = \frac{Q}{4\pi[T(t_{2})-T(t_{1})]}\  \log{\Big(\frac{t_{2}}{t_{1}}\Big)}$$</p>

Revision as of 16:41, 25 August 2016